7m^2+13m-2=0

Solution for 7m^2+13m-2=0 equation:

7m^2+13m-2=0

a = 7; b = 13; c = -2;
Δ = b2-4ac
Δ = 132-4·7·(-2)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-15}{2*7}=\frac{-28}{14}
=-2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+15}{2*7}=\frac{2}{14}
=1/7
$